Americca's neediest cities

WalletHub - WalletHub compared more than 180 U.S. cities across 28 key metrics to determine where Americans are most economically disadvantaged. The data set includes factors like the child poverty rate, food insecurity rate and uninsured rate.
 

Neediest Cities in America
1. Detroit, MI	11. Baton Rouge, LA
2. Brownsville, TX	12. Los Angeles, CA
3. Shreveport, LA	13. Fort Smith, AR
4. Cleveland, OH	14. Philadelphia, PA
5. Little Rock, AR	15. Newark, NJ
6. Gulfport, MS	16. Memphis, TN
7. Corpus Christi, TX	17. Baltimore, MD
8. Birmingham, AL	18. Houston, TX
9. Laredo, TX	19. Columbia, SC
10. New Orleans, LA	20. Las Cruces, NM

 
Key Stats

• Overland Park, Kansas, has the lowest child poverty rate, which is 11.8 times lower than in Cleveland, Ohio, the city with the highest. 
   
• Gilbert, Arizona, has the lowest adult poverty rate, which is 5.4 times lower than in Detroit, the city with the highest. 
   
• Columbia, Maryland, has the fewest homeless persons (per 1,000 residents), which is 42.2 times fewer than in New York, the city with the most. 
   
• Sioux Falls and Rapid City, South Dakota, have the lowest unemployment rate, which is 5.4 times lower than in Detroit, the city with the highest. 
   
• South Burlington, Vermont, has the lowest share of uninsured residents, which is 13 times lower than in Brownsville, Texas, the city with the highest.

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